Learn how to solve equations with one unknown variable, equations with variables on both sides, equations with parentheses, and equations with fractions–even if you’re allergic to algebra!
This algebraic equations math review is designed to refresh your knowledge for entrance exams such as ATI TEAS V, HESI, ACT, or the SAT.
What type of math is on the ATI TEAS exam? The ATI TEAS math section test participants on order of operations, ratios, fractions, metric conversation, etc. This ATI TEAS math practice quiz will test you ability to solve multiplying and dividing decimal numbers.
How to Solve Equations with One Unknown Variable
I’ll show you how to solve equations with one unknown, such as this 2x + 5 = 10. I’ll also show you how to solve equations with variables on both sides, such as 2 (x+5) = 7x + 3. In addition, I’ll do some equations with fractions x/2 + 1/3 = x/4 + 2/3.
Solving equations with an unknown variable isn’t as complicated as it first looks. There are a few principles you’ll want to keep in mind when you solve these problems. First, you’ll need to remove any parentheses. You can do this using the distributive property.
Next, you’ll want to move the variable to one side of the equation and the numbers on the other side. That’s our objective–it’s to find out what the variable (usually “x”) represents. We want our final answer to say something like x=5.
In order to isolate the variable to one side and the number to the other side, we can use a few “rules.” One rule is the addition principle, which states that we can add or subtract a number from itself to remove it from one side of the equation, but we must do the same thing to the other side of the equation to keep it balanced.
Another principle is the multiplication principle, which is similar to the addition principle. The multiplication principle states that we can multiply or divide a variable by a number to isolate it on one side of the equation, but we must do the same to the other side.
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Solve Equations with One Unknown Variable Practice Questions
1. x + 3 = 5
2. 2x + 7 = 21
3. 2(2x – 4) = x + 4
4. x/10 = 5
5. x/2 + 7 = x/6 – 1
6. 2( x/2 + 4) = 5x – 5
7. 5x + 3 = 2x + 12
8. x/3 = 5/6
1. x = 2
2. x = 7
3. x = 4
4. x = 50
5. x = -24
6. x = 3 1/4 OR 13/4
7. x = 3
8. x = 15/6 OR 2 1/2
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